3. Suppose that, in some anti-parallel universe, ability to fly (A/a) is 100% genetically determined and co-dominantly inherited. Flightal (A) is dominant, Groundling (a) is recessive and heterozygotes are Hoverants. A flight screening finds that 16% of residents in the anti-parallel universe are groundlings. A. What are the allele frequencies in the population for A and a? (1 point)

The allelic frequencies in the population for "A" is 0.6 and for "a" is 0.4

Explanation:

According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q²(Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.

In the exposed example,

What are the allele frequencies in the population for A and a?

If 16% of residents are groundlings, this means that the genotypic frequency for the trait, aa, is 0.16.

If 0.16 is the genotypic frequency for groundlings, which is aa= q²= 0.16, then we can calculate the allelic frequency by clearing the equation:

if q²= 0.16, then q = √0.16 = 0.4

So now we know that he allelic frequency for a or q is 0.4  

This means that the allelic frequency for A or p is 0.6, which we deduce by clearing the equation p + q = 1

                          p + 0.4 = 1

                         p = 1 - 0.4

                         p = 0.6

The allelic frequencies in the population for A is 0.6 and for a is 0.4

answers are:

lysogenic     viral dna merges with host cell dna

lysogenic     no symptoms

lytic               viral dna takes over

lysogenic     virus does not destroy host cell

lytic               virus destroys host cell

lytic               induces symptoms of viral infection

lysogenic       cell reproduces and spreads provirus

nb

explanation:

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