F = freckles f= no freckles
3. A man who is heterozygous for freckles marries a woman who is also heterozygous for freckles.
a. What are the two genotypes?
b. % of offspring that will be homozygous dominant
c. % of offspring that will be heterozygous
d. % of offspring that will be homozygous recessive
e. % of offspring that will have freckles
f. % of offspring that will not have freckles

a. Ff for both

b. 25%

c. 50%

d. 25%

e. 75%

f. 25%

since both are heterozygous, when you genetically cross them, the probability of getting homozygous dominant is 1/4(25%), heterozygous will be 50%, homozygous recessive is 25%, 75% will have freckles since F is the dominant for freckles. 25% will have no freckles.

A. Ff for both

B. 75%

C. 25%

D.0%

E.75%

F. 25%

Hope this helps you:)

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explanation:

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