G To answer this question, you may reference the Metabolic Map. Select the steps of glycolysis in which ATP is produced. phosphoenolpyruvate → pyruvate phosphoenolpyruvate→pyruvate glucose → glucose 6‑phosphate glucose→glucose 6‑phosphate glyceraldehyde 3‑phosphate → 1,3‑bisphosphoglycerate glyceraldehyde 3‑phosphate→1,3‑bisphosphoglycerate 1,3‑bisphosphoglycerate → 3‑phosphoglycerate 1,3‑bisphosphoglycerate→3‑phosphogl ycerate fructose 6‑phosphate → fructose 1,6‑bisphosphateSuppose 13 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the number of pyruvate molecules produced. Pi = Pyruvate =

a) Total of ATP produced in glycolysis is equal to 2

ATP produced:

i) 1,3‑bisphosphoglycerate → 3‑phosphoglycerate (2 ATP are produced)

ii) phosphoenolpyruvate→pyruvate (2 ATP are produced)

b) 26 pyruvate molecules.

Explanation:

a) Glycolysis consists of two steps in which ATP is consumed and two steps in which ATP is released.

ATP produced = 4

ATP consumed = 2

The total of ATP produced in glycolysis is equal to 2 (4-2)

ATP produced:

i) 1,3‑bisphosphoglycerate → 3‑phosphoglycerate (2 ATP are produced)

ii) phosphoenolpyruvate → pyruvate (2 ATP are produced)

b) In the sixth step of glycolysis, inorganic phosphate molecules are consumed:

glyceraldehyde-3‑phosphate → 1,3‑bisphosphoglycerate

2 pi are added in glycolysis. As each glucose molecule undergoes glycolysis, the pi required by the 13 glocosa molecules is 26 (13 * 2).  Glycolysis of each glucose produces 3 pyruvates, so 13 glucose molecules will produce 26 pyruvate molecules.

enzyme active site and substrate specificity

enzymes bind with chemical reactants called substrates. there may be one or more substrates for each type of enzyme, depending on the particular chemical reaction. in some reactions, a single-reactant substrate is broken down into multiple products