In humans, black hair (B) is dominant over blonde hair (b) and brown eyes (E) are dominant over blue eyes (e). If a man that is heterozygous for both traits is crossed with a woman that is heterozygous for both traits, what are the chances of producing an offspring that is heterozygous for both traits?

In humans, black hair (B) is dominant over blonde hair (b) and brown eyes (E) are dominant over blue eyes (e). If a man that is heterozygous for both traits is crossed with a woman that is heterozygous for both traits, what are the chances of producing an offspring that is heterozygous for both traits?

BbEe x BbEe= BBEE, BbEe, BbEe, and bbee

the chances for producing offspring that is heterozygous for both traits is 50%

Explanation:

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.