Ralph has type B blood and his wife Rachel has type A blood. They are very shocked to hear that their baby has type O blood, and think that a switch might have been made at the hospital. Can this baby be theirs? Show your work. TA 1 4. In dogs, wire hair (S) is dominant to smooth (s). In a cross of a homozygous wire- haired dog with a smooth-haired dog, what will be the phenotype of the F, generation?

1. The parents genotypes could have been BO and AO

2. wire-hair

Explanation:

There are four possible blood types which are type A, B, AB, O. blood group is the classification of blood based on the presence or the absence of inherited antigenic substances on the surface of the red blood cells. They have hereditary basis and also rely on a series of alternative genes sometimes used in solving dispute of parental heritage. With the four possible blood groups, there are six possible genotypes and these are:

Blood type               possible genotypes

Type A                         AA, AO

Type B                         BB, BO

Type AB                           AB

Type O                              OO

Thus, for parents with blood type B and A to give birth to a child with blood type O, it means their genotype could have been both BO and AO  for them to be able to produce a child with OO. a cross between these two could give rise to OO.

Question 2

Wire hair is dominant (S) to smooth (s), thus wire hair could be in the homozygous (SS) and heterozygous form (Ss) and the smooth hair can only be expressed in the homozygous recessive form (ss).

thus, in a cross between homozygous wire haired and smooth haired, we will have:

homozygous wire haired            homozygous smooth haired

P gen              SS                x               ss

F1 gen.                                Ss

phenotype:                     wire haired

the answer is cell division : )