In humans, blood can be either Rh-positive or Rh-negative. Rh-positive individuals have the Rh antigen in their blood; Rh-negative individuals do not. The Rh-positive allele is dominant (A) while the Rh-negative allele is recessive (a). If 84% of the population is Rh-positive, what is the frequency of the Rh-positive allele (A)

0.60

Explanation:

q2 = 0.16;

q = 0.4

Using the formula: p = 1 − q,

P = 1 - 0.4

p = 0.6

or p = 60%

Cheers

The correct answer is: 0.60.

Explanation:

According to the Hardy-Weinberg equilibrium, the genotypic frequencies are: freq AA = p² , freq Aa = 2pq , and freq aa = q².

p refers to the frequency of the dominant allele, in this case that would be Rh-positive; while q refers to the frequency of the recessive allele, Rh-negative.

If 84% of the population is Rh-positive, that means that 16% of the population is Rh-negative (aa).

q² = 0.16

q = √0.16

q=0.4

p + q always equals 1, so:

p = 1 - 0.4

p = 0.6

the answer will be a) proteins i believe