Assuming H-W equilibrium, find both the allele and genotype frequencies. a. In Drosophilia, the allele for normal length wings is dominant over the allele for vestigial wings. In a population of 1,000 individuals, 160 show the recessive phenotype.

Hardy Weinberg Equilibrium

Explanation:

The frequency of the prevailing (typical) allele in the populace (p) is basically 1 - 0.02 = 0.98 (or 98%). The level of heterozygous people (bearers) in the populace. 2pq equivalents the recurrence of heterozygotes or transporters, at that point the condition will be as per the following: 2pq = (2)  .The every individual's genotype, check the quantity of duplicates of every allele, and separation by the total number of gene copies. Sickle cell attribute was identified in 20.2% of populace though 1.2% was influenced with sickle cell iron deficiency. The allele recurrence of HbA and HbS alleles were 0.89 and 0.11. p2 speaks to the recurrence of the homozygous genotype AA, q2 speaks to the recurrence of the homozygous genotype aa, and 2pq speaks to the recurrence of the heterozygous genotype Aa. The entirety of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.

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