In humans, free earlobe are dominant to attached earlobe, and a straight thumb is dominant to a hitchhikers thumb. Cross two people that are heterozygous for both traits.

The correct answer is - the phenotypic ratio would be 9:3:3:1.

Explanation:

The two traits that are dominant are free earlobe and straight thumb that are denoted by the E and T on their alternative recessive alleles attached lobe and hitchhiker thumbs denoted by the e and t respectively. The heterozygous condition will be EeTt.

The cross between EeTt and EeTt will produce gametes ET, Et, eT, and et by each. The phenotypic ratio of the cross would be 9:3:3:1, which means 9 out of 16 offspring will be dominant in both trait, 3 will be free lobe and hitchhiker thumb, 3 will be straight thumb and attached earlobe, and 1 will be recessive in both traits. For the cross please check the attached image.

Thus, the correct answer is - the phenotypic ratio would be 9:3:3:1.

the oxygenated blood then leaves the lungs through pulmonary veins, which return it to the left heart, completing the pulmonary cycle. this blood then enters the left atrium, which pumps it through the mitral valve into the left ventricle. from the left ventricle, the blood passes through the aortic valve to the aorta.

deoxygenated blood leaves through the right ventricle through the pulmonary artery. from the right atrium, the blood is pumped through the tricuspid valve (or right atrioventricular valve), into the right ventricle.

thinking it would be physical characteristics