The occurrence of the same amino acid sequence in the digestive proteins in two species provided evidence that these two species

Explanation:

If each nucleotide determined an amino acid, we could only code four

different amino acids since in DNA there are only four different nucleotides. Figure very

less than the 20 different amino acids that exist.

If every two nucleotides will encode an amino acid, the total number of different dinucleotides

that we could achieve with the four different nucleotides (A, G, T and C) would be variations

with repetition of four elements taken two at a time VR4,2 = 42 = 16. Therefore,

we would have only 16 different dinucleotides, less than the number of amino acids

different that exist (20).

If each group of three nucleotides determines an amino acid. Given that they exist

four different nucleotides (A, G, T and C), the number of groups of three different nucleotides

that can be obtained are variations with repetition of four elements (the four

nucleotides) taken three at a time: VR4.3 = 43 = 64. Therefore, there is a total of 64

different triplets, more than enough to code the 20 different amino acids.

the answer to your question is b