When culturing a chemoorganoheterophic bacterium, what outcome is LEAST likely to occur if ammonia and phosphate are provided at equal concentrations?

Options:

A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.

B) Cells will never consume all of the phosphate, because N is needed in higher quantities than P.

C) The final biomass of cells will be no different than if only 50% of the phosphate was provided.

D) The bacteria will import all of the ammonia to use for biosynthetic pathways.

A) Cells require much less P to grow than N, so extra P will be used for ATP synthesis and result in a faster growth rate.

Explanation: Chemoorganoheterophic Bacteria are bacteria which requires the supply of organic nutrients of Carbon and metabolic energy. If Ammonia and potassium are provided at equal amount or concentration, the least likely occurrence will be that

Cells require much less P(potassium) to grow than N(Nitrogen), so extra P(potassium) will be used for ATP synthesis and result in a faster growth rate. This is so because Chemoorganoheterophic Bacteria requires organic supply of nutrients in the form of Carbon and metabolic energy.

answer: because

explanation: idk