Consider a population of 1099 apple fly maggots. In this population, you observe that the allele frequency of the dominant allele at the ADH locus, where are are two alleles, is 0.554. What is the expected number of heterozygotes if this population is at HWE (please give your answer as an integer)?

543

Explanation:

Given is the frequency of the dominant allele in the population (p)= 0.554

Since the locus has two alleles and the population is in Hardy Weinberg equilibrium, the frequency of the recessive allele (q) of the same locus would be= 1-0.554= 0.446

Frequency of heterozygous genotype in the given population = 2pq= 2 x 0.554 x 0.446= 0.4941

Now, the number of heterozygous genotype in the given population= 0.4941 x 1099= 543.0159 = 543

the overall balanced equation

6co2 + 6h2o > c6h12o6 + 6o2

sunlight energy

where: co2 = carbon dioxide

h2o = water

light energy is required

c6h12o6 = glucose

o2 = oxygen

an active site is a region that is present on an enzyme where the reactants or the substrate molecules we can say bind and experience a chemical reaction. the substrate is basically a reactant whose concentration is changing and that is converting into a product after binding at the active site of an enzyme