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Phenotype ratio is two heterozygous round pea : two homozygous wrinkled pea

Probability of getting a wrinkled pea is 1/2

The number of flowers that are homozygous is 2

The probability of getting a round pea is 1/2

Genotype ratio = 2 Rr : 2 rr

Explanation: From the information provided, round pea R is dominant while wrinkled pea r is recessive. A monohybrid cross between a heterozygous round pea Rr and a homozygous wrinkled pea rr will produce four offsprings, two of which are heterozygous round pea Rr and the other two are homozygous wrinkled pea rr.

The genotype ratio is 2 Rr : 2 rr while the phenotype ratio is two heterozygous round pea : two homozygous wrinkled pea. Heterozygous round (Rr) peas will manifest outwardly as round pea because R is dominant while r is recessive.

Since two out of the four offsprings are homozygous wrinkled pea, therefore the probability of getting a wrinkled pea is 2/4 = 1/2. Also, two out of the four offsprings are heterozygous round pea, therefore the probability of getting a round pea is 2/4 =1/2.

Since, only the two wrinkled peas are homozygous, therefore the number of flowers that are homozygous is 2

estuaries are the partially enclosed coastal bodies of brackish water formed at the mouth of sea where river meets an ocean. it is a transition zone between river and sea water so estuaries are influenced to both marine environment such as tides, waves and to riverine such as flow of fresh water and sediments. the mixing of sea and fresh water provide high level of nutrients, making estuaries a high product habitats.

many estuaries suffers degradation from a variety of human activities like erosion from deforestation, overgrazing, overfishing, drainage and eutrophication.

so from the above statement answers will be

1. false as estuaries are formed due to both brackish and freshwater.

2.true, due to high productivity estuaries are breeding ground for many marine species.

3. direct and indirect activities of man that contribute to pollution and deposition of sediments.

1) a

2)c

3)a

4)c

5)b

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