A woman and a man are both heterozygous for a recessive allele for a rare genetic disease. If they have one child, what is the probability that he or she will be affected? If they have two children, what is the probability that at least one of them will be affected?

3/4, 7/16
1/4, 7/16
1/4, 3/4
3/4, 1/4
7/16, 1/4

Probability that at least one of them will be affected = 3/16 + 3/16 + 1/16 = 7/16

Explanation:

If both parents are heterozygous for a genetic disease; Xx and Xx

The offspring's they will produce will be as follows ; XX, Xx, xX, xx

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