A woman who is a nontongue roller marries a man that is heterozgyous for rolling his tongue. What percent of the children will be able to roll their tongue? Image result for tongue rolling genetics Tongue Rolling is a dominant trait (actually this is a myth described by Alfred Sturtevant, genetist in 1940- we will just go with it).
a 100%
b 75%
c 50%
d 25%
e 0%

The answer to your question is letter C. 50%

Explanation:

According to the information given we know that non-tongue rolling a recessive trait and tongue rolling is a dominant trait so

For the woman, we have   tt            the woman is homozygous

and for  the man, we have  Tt           the man is heterozygous

Punnet's square

                                       T       t

                                 t     Tt      tt

                                t     Tt      tt

50% of the children would be able to roll the tongue

50% of the children would not be able to roll the tongue

C) 50%

Explanation: The information provided shows that tongue rolling is dominant while non tongue rolling is recessive. Let R represent the allele for tongue rolling and r represent the allele for non tongue rolling, therefore a man who is heterozygous for tongue rolling will have a genotype Rr and a woman who is a non tongue-roller will have a genotype of rr. A cross between them will produce offsprings with genotypes Rr and rr. Rr is being heterozygous for tongue rolling while rr is being a non tongue roller. Fifty percent of the offsprings will be tongue rollers while fifty percent will be non tongue rollers.

See the punnett square attached

it is called the mitotic spindle