In a certain population of rabbits, the allele for brown fur is dominant over the
allele for white fur. if 10 out of 100 rabbits have white fur, what is the allele
frequency for the dominant allele?
the hardy-weinberg equation is:
[homozygous dominant]2 + 2[heterozygous] + [homozygous recessive]2 = 1
o a. 0.95
o b. 0.90
o c. 0.68
o d. 0.10

The allele  frequency for the dominant allele is 0.68.

C. 0.68

Explanation:

Let,

The Brown dominant allele be BB

The white recessive allele be bb

Frequency of white fur rabbit (bb) = 10/100 = 0.1

Therefore, q2 = 0.1

Frequency of recessive allele, q= √0.1

                                                  q = 0.316

Using Hardy Weinberg equation:

p+q = 1

p = 1-q

p = 1-0.316

p = 0.684

Thus, frequency of dominant allele, p = 0.684

interphase

the period of cell growth when the cell synthesizes new molecules and organelles. the cell is not dividing and it constitutes the majority of the time spent in the cell cycle

prophase

changes occur in the nucleus and cytoplasm. the chromatin condenses to form structures (sister chromatids) visible with a light microscope and the mitotic spindle begins to form, but the nucleus is still in tact

prometaphase

the nuclear envelope fragments and the spindle microtubules attach to the kinetochores of the sister chromatids

metaphase

all the cell's duplicated chromosomes are lined up at an imaginary plane equidistant between the poles of the mitotic spindle

anaphase

begins when sister chromatids separate from each other and ending when a complete set of daughter chromosomes arrives at each of the two poles of the cell

telophase

the daughter nuclei form at the two poles of a cell

cytokinesis

the division of a cytoplasm to form two separate daughter cells. usually occurs during telophase during mitosis. this and mitosis make up to mitotic (m) phase of the cell cycle