In some bees, thin stripes (s) are dominant over thick stripes (s) and black eyes (b) are dominant over gray eyes (b). complete a dihybrid cross for parents with the genotypes: ssbb × ssbb and answer the following in complete sentences.
1. describe how you would set up a punnett square for this cross.
2. list the likelihood of each possible offspring genotype.
3. list the likelihood of each possible offspring phenotype.
(5 points)

There are three parts of this question:

1:Describe how you would set up a Punnett square for this cross.

For making a punnet square we need to cross the given parent details:

P1: SsBB × ssBb

Gametes: SB: sB : sb

Now we will easily draw a cross which is depicted in attached image.

2. List the likelihood of each possible offspring genotype.

As it is mentioned in the question that , thin stripes (S) are dominant over thick stripes (s) and black eyes (B) are dominant over gray eyes (b). Now we see below genotypes in below mentioned ratio:

Genotype: SsBB: ssBB: SsBb: ssBb  

Ratio:           4       :  4   :    4    :    4

It means that Likelihood genetic occurences is as:

SsBB: 25 % ,  ssBB: 25 %, SsBb:25 % and ssBb:25 %

3: Likelihood of phenotypic ratio is as:

Hope it helps!

if the hares very faster than they are now, and thus the lynx's hunting success rate drops because it will be harder to catch them, the rate that will change will be the pray-rate. the pray-rate will change because more hares will be able to survive, thus more individuals for reproduction, so the end result will be increasing population of hares.

the predator-rate will remain pretty much the same because there will be more than enough pray, but the hunting success rate is stagnant.