Consider a cross between individuals that are: aabbccdd and aabbccdd in which all genes segregate independently. what frequency of progeny will have the same genotype as the aabbccdd parent?

1/16

Explanation:

The genotype of parents: AaBbCcDd and AAbbccDD

To calculate the frequency of a child with a specific genotype, we can calculate the individual frequencies for each gene and apply the product rule to calculate the overall frequency.

Aa x AA = 1/2 Aa: 1/2 AA

Bb x bb = 1/2 Bb: 1/2 bb

Cc x cc = 1/2 Cc: 1/2 cc

Dd x DD= 1/2 DD: 1/2 Dd

Therefore, the frequency of a progeny with genotype AAbbccDD = 1/2 AA x 1/2 bb x 1/2 cc x 1/2 DD = 1/2 x 1/2 x 1/2 x 1/2 = 1/16 or 0.0625 .

bc blah

explanation:

bc blah

water is a polar molecule. a chemical bond is a force of attraction between atoms or ions. bonds form when atoms share or transfer valence electrons. atoms form chemical bonds to achieve a full outer energy level, which is the most stable arrangement of electrons. so, false

explanation:

in h2o molecule, two water molecules are bonded by a hydrogen bond but the bond between two h - o bonds within a water molecule are covalent. the greater the electronegativity difference, the more ionic the bond is. bonds that are partly ionic are called polar covalent bonds. nonpolar covalent bonds, with equal sharing of the bond electrons, arise when the electronegativities of the two atoms are equal.