If 70% of the hypothetical population passed along allele b, the dominant allele for brown eyes, and 30% passed along allele b, the recessive allele for blue eyes, the proportion of the subsequent generation with brown eyes would be given hardy-weinberg equilibrium.
a. 28%
b. 70%
c. 91%
d. 99%

C) 91%

Explanation:

First,

Express the Dominant phenotype as homozygous dominant(BB) and heterozygous(Bb).

Based on hardy-Weinberg equilibrium,

homozygous dominant (BB) Brown eye individuals will have the following percentage

B × B

(Where B = 70%)

70% × 70%

= 49%

heterozygous dominant (Bb) Brown eye individuals will have the following percentage

Using 2 × B × b (where B =70% and b = 30%)

2 × 70% × 30%

= 42%

The proportion of the subsequent generation with brown eyes

(homozygous dominant, BB + heterozygous dominant, Bb)

= 49% + 42%

= 91%

i think it is dna, i'm not totally sure but i think it might be.