In humans , straight thumbs are dominant to hitchhiker's (bent) thumbs. what is the probability the offspring will have straight thumbs if you cross a homozygous dominant female with a heterozygous male?

a) 0%

b) 25%

c) 50%

d) 100%

50%

Explanation:

I just did the punnett square here on paper I used the letter T for both parents. Tt is for the farther and tt is for the mother. Square 1 is Tt, Square 2 is tt, Square 3 is Tt, and Square 4 is tt. Proof it is 50% of the genes from both mother and father will go off into the offspring. If they have 2 offsprings 25% straight thumb 25% Hitchhiker thumb.

sorry, but you do not have posted the diagram.

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.