If a germ-line cell from a frog contains 10 picograms of dna during g1 of interphase, then how many picograms of dna would be present in each cell during prophase ii of meiosis? (enter the number only, not the units.)

10

Explanation:

The cell cycle is composed of three states: interphase, cell division and resting.

The interphase is composed of 3 phases: G1, S and G2 (in this order). During this state the cell prepares itself  for cell division. As part of the preparation the cell duplicates all its genetic material, that is, all its chromosomes. This duplication is done during the phase S.

During the meiotic cell division (composed of meiosis 1 and meiosis 2) a single diploid mother  cell (with duplicated chromosomes) produces four haploid daughter cells. the meiosis 1 produces two haploid cells with duplicated chromosomes, and the meiosis 2 produces 4 haploid cells with normal chromosomes (no duplicated).

If a germ-line cell from a frog contains 10 picograms of DNA during G1, then this cell will have 20 picograms of DNA before the product of the first meiotic division, and will have 10 picograms at the begining of the meiosis 2 (i.e prophase II)

producers: apple trees, potatoes, carrots, grains, acorns, cabbage, grass, corn, lettuce

consumers: deer, mice, rabbits, chickens, squirrels, horses, worms, cows

predators: eagles, frogs, wolves, owls

in 1859, charles darwin set out his theory of evolution by natural selection as an explanation for adaptation and speciation. he defined natural selection as the "principle by which each slight variation [of a trait], if useful, is preserved".