Phenotypically identical
(1) the female parent: 9/64
(2) the male parent: 9/64
(3) either parent: 9/32
(4) neither parent: 23/32
Genotypically identical
(1) the female parent: 1/16
(2) the male parent: 1/16
(3) either parent: 1/8
(4) neither parent: 7/8
Explanation:
To find out the answers, we will have to find out probability of each gene separately:
female male
A/a;B/b;c/c;D/d;e/e A/a;b/b;C/c;D/d;e/e
If we will look at only A gene combinations in both the parents the results will be as under:
Parentals : A/a x A/a
The 4 gametes in the progeny will be as under :
AA = 1/4
Aa = 1/4 Combined probability of Aa = 1/4+ 1/4 = 1/2
Aa = 1/4
aa = 1/4
If we will look at only B gene combinations in both the parents the results will be as under:
Parentals : B/b x b/b
The 4 gametes in the progeny will be as under :
Bb = 1/4 Combined probability of Bb = 1/4+ 1/4 = 1/2
Bb = 1/4
bb = 1/4 Combined probability of bb = 1/4+ 1/4 = 1/2
bb = 1/4
If we will look at only C gene combinations in both the parents the results will be as under:
Parentals : c/c x C/c
The 4 gametes in the progeny will be as under :
Cc = 1/4 Combined probability of Cc = 1/4+ 1/4 = 1/2
Cc = 1/4
cc = 1/4 Combined probability of cc = 1/4+ 1/4 = 1/2
cc = 1/4
If we will look at only D gene combinations in both the parents the results will be as under:
Parentals : D/d x D/d
The 4 gametes in the progeny will be as under :
DD = 1/4
Dd = 1/4 Combined probability of Dd = 1/4+ 1/4 = 1/2
Dd = 1/4
dd = 1/4
If we will look at only E gene combinations in both the parents the results will be as under:
Parentals : e/e x e/e
The 4 gametes in the progeny will be as under :
ee = 1/4
ee = 1/4 Combined probability of ee = 1/4+ 1/4 + 1/4 +1/4 = 1
ee = 1/4
ee = 1/4
It is given that genotype of first parent is A/a;B/b;c/c;D/d;e/e or AaBbccDdee .
Also, it is pertinent to mention here that AA and Aa genotype will produce same kind of phenotype. In the progeny, we can calculate the probability of AA & Aa will be 1/4 + 1/2 = 3/4
Similarly with respect to gene B, BB and Bb will produce same kind of phenotype but BB genotype will not get produced so we will only find out probability of Bb alone which is 1/2
Similarly the allelic combinations of gene C which will be similar to first parent will be 1/2
The combinations of gene D which will be similar to first parent will be a combination of DD & Dd which is 1/4 + 1/2 = 3/4
For gene e the combinations which will produce same phenotype as of first parent will be 1 because all the combinations are ee.
CALCULATIONS FOR PROGENY WHICH ARE SIMILAR TO PARENTS PHENOTYPICALLY.
(1) So, the combined probability of resemblance of phenotype of progeny with first parent which is female = 3/4 x 1/2 x 1/2 x 3/4 x 1 = 9/64.
(2) The genotype of male parent is A/a;b/b;C/c;D/d;e/e or AabbCcDdee.
So, in a similar way we can find out the combined probability of resemblance of phenotype of progeny with second parent = 3/4 x 1/2 x 1/2 x 3/4 x 1 = 9/64
(3) The progeny which are similar to either parent will be 9/64 + 9/64 = 18/64 = 9/32.
(4) The progeny which will have phenotype which does not match any parent will be 1 - 9/32 = 32 - 9 /32 = 23/32.
CALCULATIONS FOR PROGENY WHICH ARE SIMILAR TO PARENTS GENOTYPICALLY.
When we will look for progeny which are genotypically similar to parents, we will look for allelic combinations which are exactly similar to parents. While finding genotypes, homozygous dominant and heterozygous will not be same. For example, AA and Aa will not produce same genotype.
(1) The probability of progeny which will be genotypically identical to female parent (AaBbccDdee) is 1/2 x 1/2 x 1/2 x 1/2 x 1 = 1/16.
(2) The probability of progeny which will be genotypically identical to male parent (AabbCcDdee) is 1/2 x 1/2 x 1/2 x 1/2 x 1 = 1/16.
(3) The progeny which will be genotypically similar to either parent will have probability = 1/16 + 1/16 = 1/8
(4) The progeny which will have genotype which does not match any parent will be = 1 - 1/8 = 7/8
