G6pd deficiency in humans is an x-linked recessive trait. if a homozygous dominant female (xgxg) has children with an affected male (xgy), then what is the probability of the children being carriers?

Only the daughters will be carriers and the probability is 1 or 100%

Explanation:

Homozygous dominant female =

Affected male =

  x  

Offspring = (female), (females), (male), (male)

For X-linked traits, male gender can either be affected or not affected, they cannot be carriers because the Y chromosome is hypothesized to not carry any gene. Since the two X chromosomes in female carry genes, they can be carriers for X-linked traits.

Considering the female children only, the probability is 1 or 100%.