You perform a cross with a mouse with black for in a mouse with whitefir which results for the offspring would indicate that the mouse with blackbear was heterozygous

If the mouse with black fur is heterozygous, this indicates the black is the phenotype formed by the dominant alleles. Let B be the dominant allele for black fur and b be the recessive allele for white fur. If the mouse with black fur is heteozygous, it would have the genotype Bb and the mouse with white fur would have the genotype bb. Bb x bb would result in offspring genotypes of Bb (black) and bb (white) in equal ratio. Comparatively, if the black fur mouse was homozygous dominant BB, BBx bb would result in all offspring genotype of Bb (black)

Hence the presence of offsprings with white fur would indicate that the mouse with black fur was heterozygous.

1. a host loses nutrients to a parasite

2. a parasite only benefits when the host is alive (cause if the host dies the parasite dies with it )

3. producers to consumers

4. the tapeworm is a parasite

5. they convert energy from the sun (photosynthesis)

6. sunflower-robin (i think im 80% sure)

7. producer

8. consumer

9. prey

10. fresh water snails ( cause the green algea is the producer and the snails are the primary consumers and the small fish consumer so is the big fish)