In humans, red blood cells have a number of proteins embedded in the cell membrane. one type of protein, the rh factor, is controlled by a single gene and is either present or missing from the red blood cells. if present, the individual has the rh+ phenotype. of missing, the individual has the rh− phenotype. rh+ is the dominant to rh−. suppose that, in the welsh population, the frequency of the rh− phenotype is 0.04. using the hardy–weinberg equations, calculate the frequency of the rh allele to at least two decimal places.

Frequency of Rh-= 0.20

Frequency of Rh+ = 0.80

Explanation:

According to the given information, the allele Rh- is recessive to the allele Rh+. The given frequency of homozygous recessive genotype (Rh-Rh-) in the Welsh population is 0.04

Therefore, the frequency of homozygous recessive phenotype in the population (q^2)= 0.04

The frequency of recessive allele (Rh-)= square root of 0.04 = 0.20

Since the population is in Hardy–Weinberg equilibrium, p+q=1

Here, p= frequency of dominant allele

q = frequency of recessive allele

Since the frequency of a recessive allele (q)=0.2 0

So, frequency of dominant allele (p)= 1-0.2 = 0.8 0

the answer is

c. parental

the "dirty dozen" chemicals banned in an international treaty are formally known as persistent organic pollutants, or pops. the united nations environment program provided this background on what they are and what they can do to humans and wildlife.

i hope this