When you ride a bicycle, your foot pushes down on a pedal that’s 17.5 cm (0.175 m) from the axis of rotation. your force produces a torque on the crank attached to the pedal. suppose that you weigh 700 n. if you put all your weight on the pedal while it’s directly in front of the crank’s axis of rotation, what torque do you exert on the crank?

Torque = 122.5 kgm²/s²

Explanation:

Given

Force, F = 700N

Distance between a center of rotation and a force, d = 0.175 m

θ = rotational angle

Because you're pushing down as the crank is right in front of the axis of rotation; without considering angle between the force and the axis of rotation; torque is calculated as follows.

Torque = Force * Distance

Substitute for each value

Torque = 700 * 0.175

Torque = 122.5 kgm²/s²

there are 35 white marbles

step-by-step explanation:

y- yellow marbles

4y + 5 = 45

subtract 5 from both sides

4y = 40

divide for from both sides

y = 10

plug in 10 to get 40 yellow marbles then subtract by 5 to get 35 marbles

thus there are only 10 yellow marbles