How many ml of water would be displaced by 408 g of lead

The formula you are going to use for this question is the density formula, which states that: D = M/V, 
Where D = density = 11.34 g/cm3
M = mass of lead = 408g
V = volume of water displaced = ?
D = M/V 
Make V the subject of the formula
V = M/D = 408/11.34 = 35.98
V = 35.98 ml.
Thus, 35.98 ml of water will be displaced by the lead.