Brown hair (b) is dominant to blond hair (b). there are 150 brown haired people in a population of 200.
a. what is the frequency of heterozygotes?
b. what is the frequency of homozygous dominant?
c. what is the frequency of the b allele?

a. What is the frequency of heterozygotes? 50%, heterozygotes are the ones that have one of each alelle (B and b). They will have brown hair as a phenotype.

b. What is the frequency of homozygous dominant? 25%, homozygotes are the ones that have the same allele twice (BB). They will also have brown hair.

c. What is the frequency of the b allele? 75%, compound of 50% brown hair and 25% blond hair.

150 represents 75% of 200. To achieve this percentage, two heterozygotes have to be cross:

                                          Bb × Bb  

                                  ↓       ↓       ↓      ↓

                                 BB     Bb    bB    bb

Because brown hair is dominant, each pair of alleles that has a B will have brown hair as a phenotype.

The pair of alleles that has 2b is the only one that will have blond hair (in this case 25%).  

so whats the answer

a. population growth is decreasing

-2

+4

-10

-3

-8

-3

so the population decreased by 24 because 3+3+8+10+2=26-2=24.

hoped i !

explanation: