Iwill mark as brainliest and 20 points the table shows the solubility of two substances in water at 20 °c.

part 1: what will be the values of l and k for 100 kg of each substance?
part 2: explain your answer for part 1.

answer:

i can't understand the table clearly, so i'm solving it with some assumptions i think is closest to what u wanted to say.

in case of sodium chloride;

mass of water = 100 kg

solubility of nacl = 54 g / 100 g of water

thus the mass of nacl needed for full saturation, l = (54/100) x 100 kg = 54 kg

in case of lead nitrate;

mass of water = 200 kg

mass of pbno₃ = 36 kg

if the solution is fully saturated, solubility of pbno₃ (g per 100 g of water)

k = (36/200) x 100 g   = 18 g

k can be also written as 18 kg per 100 kg of water.

thus the difference in k and l = (54-18) = 36.

a covalent bond, specfically triple bond

estuaries are the partially enclosed coastal bodies of brackish water formed at the mouth of sea where river meets an ocean. it is a transition zone between river and sea water so estuaries are influenced to both marine environment such as tides, waves and to riverine such as flow of fresh water and sediments. the mixing of sea and fresh water provide high level of nutrients, making estuaries a high product habitats.

many estuaries suffers degradation from a variety of human activities like erosion from deforestation, overgrazing, overfishing, drainage and eutrophication.

so from the above statement answers will be

1. false as estuaries are formed due to both brackish and freshwater.

2.true, due to high productivity estuaries are breeding ground for many marine species.

3. direct and indirect activities of man that contribute to pollution and deposition of sediments.