Considering the same population of cats as in part a, what is the expected frequency of each genotype (tltl, tlts, tsts ) based on the equation for hardy-weinberg equilibrium? keep in mind that you just learned in part a that: the allele frequency of tl is 0.4. the allele frequency of ts is 0.6. the equation for hardy-weinberg equilibrium states that at a locus with two alleles, as in this cat population, the three genotypes will occur in specific proportions: p2+2pq+q2=1 enter the values for the expected frequency of each genotype: tltl, tlts, and tsts. enter your answers numerically to two decimal places, not as percentages. for applying the hardy-weinberg equation to this cat population, see hints 1 and 2.

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

So, if the population is in balance:

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

I hope you have a SUPER day!

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