Use the punnet squares interactive, level 3 to conduct a cross between a man with normal vision and a woman with the gene for color blindness. a man with normal vision, xb y, and a woman who is a carrier for color blindness, xb xb, mate. how many total phenotypes result from this cross? number of phenotypes: what percentage of male offspring will be color‑blind? color‑blind male offspring: % if the father were color‑blind, what percentage of male offspring would be color‑blind? color‑blind male offspring:

1) The resulting phenotypes are: Woman and man with normal vision, woman with normal vision and carrier for the color blindness and man with color blindness.

2) 25% (1/4) man with color blindness.

3) 25% (1/4) man with color blindness.

Explanation: For the cross a woman carrier for color blindness and a man with normal vision, the resulting phenotypes are: 1) woman with normal vision (25%), 2) Woman carrier of the mutation (25%), 3) man with normal vision (25%), 4) man with color blidness (25%).

For the cross a woman carrier for color blindness and a man with color blindness, the resulting phenotypes are: 1) woman with color blindness (25%), 2) Woman carrier of the mutation (25%), 3) man with normal vision (25%), 4) man with color blidness (25%).

they fuse to form they have half as many chromosomes as a somatic cell of the same individual. b