Camp activates camp-dependent protein kinase by
bindingregulatory subunits and inducing their release from the
catalyticsubunits.
stimulating itsphosphorylation.
stimulating thedimerization of kinase subunits.
stimulating therelease of a translational inhibitory protein
bound to itsmrna.

binding regulatory subunits and inducing their release from the  catalytic subunits

Explanation:

cAMP molecules diffuse into the cytoplasm where they bind to an allosteric site on a regulatory subunit of a cAMP-dependent protein kinase ( protein kinase A,  PKA).

-In its inactive form, PKA is a  heterotetramer comprised of two subunits namely, regulatory (R) and two catalytic (C) subunits.

-The regulatory subunits normally inhibit  the catalytic activity of the enzyme. cAMP binding causes the  dissociation of the regulatory subunits, thereby releasing the  active catalytic subunits of PKA.

-cAMP stimulates glucose mobilization by  activating a protein kinase that adds a phosphate group  onto a specific serine residue of the glycogen phosphorylase  polypeptide.

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.

p

explanation: