If a single bacteriophage infects one e. coli cell present on a lawn of bacteria and, upon lysis, yields 175 viable viruses, how many phages will exist in a single plaque if 3 more lytic cycles occur? enter your answer to three significant digits (for example: 1.11*10^3).

9.378*10^8

Explanation:

The number of phages in each cycle

The number of host infected in each cycle

The number of phages released by each hosts in each turn  

There are total cycle .

So the total number of phages that exist in a single plaque if 3 more lytic cycles occur

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.