The prepartory reaction breaks: a)glucose into pyruvates. b)pyruvates into glucose. c)pyruvates into acetyl-coa and carbon dioxide. d)pyruvates into acetyl-coa and water. e)acetyl coa into pyruvates and carbon dioxide.

C. pyruvates into acetyl-CoA and carbon dioxide.

Explanation:

In the preparatory reaction, pyruvates break down into acetyl-CoA and carbon dioxide. This is by the following process.

In the preparatory reaction the preparation for electron transfer and phosphorylation of ADP takes place using the energy of ATP hydrolysis.

In the preparatory reaction glucose is phosphorylated twice by ATP and cleaved into two phosphate trioses. At this stage, the cell spends two ATP molecules, the Mg2 + cation is indispensable for the reactions, and five biochemical reactions are processed. No energy is stored, on the contrary, two ATP molecules are invested in phosphorylation reactions.

Until the end of the preparatory feed no oxidative reaction occurs, and 2 ATP are used. Therefore, this phase is named after two spent ATP molecules from glyceraldehyde-3-phosphate, with a positive balance of 2 ATP and 2 Pyruvates which will be broken down into acetyl-CoA and carbon dioxide.

true is the final answer!