Both a man and a woman are heterozygous for freckles. freckles ( f) are dominant over no freckles ( f). what is the chance that their child will have freckles?

75% chance or 3/4

Explanation:

If both parents are heterozygous and freckles is a dominant trait (F) then we can denote having no freckles as (f)

Using a punnett square, this will produce the following genotypes of the children:

FF, Ff, Ff and ff.

Therefore, there's a 3 out 4 chance or 75% of the children also inheriting freckles.

complete the square on the right side of the equation;

-5(x + 0)^2 + 15

answer: d. y = -x^2 + 15

b ti isnfornopgnoernfrof