In watermelons, bitter fruit (b) is dominant over sweet fruit (b), and yellow spots (s) are dominant over no spots (s). the genes for these two characteristics assort independently. a homozygous plant that has bitter fruit and yellow spots is crossed with a homozygous plant that has sweet fruit and no spots. the f1 are intercrossed to produce the f2. what will be the phenotypic ratio in the f2?

9 Bitter and yellow spots

3 Bitter and no spots

3 Sweet and yellow spots

1 sweet and no spots

Explanation:

According to the given question, a homozygous plant with bitter fruit and yellow spots (BBSS) is crossed with a homozygous plant that has sweet fruit and no spots (bbss).

The F1 progeny would have bitter fruits with yellow spots. Crossing the F1 would obtain F2 progeny. As per the cross, the F2 progeny would have phenotypic ratio of 9 Bitter and yellow spots: 3 Bitter and no spots: 3 Sweet and yellow spots: 1 sweet and no spots.

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explanation:

the titanic would be the correct answer