Lateral inhibition occurs in most sensory systems. if a large area of the sensory periphery were stimulated in such a system (let’s say the somatosensory system: this means a large area of the skin were stimulated), a) how would the rate of firing from a mechanoreceptor in the middle of the area compare to the firing of the same mechanoreceptor if a small spot in the middle of the area were stimulated? (assume the small spot was large enough to just fill the center of the cell's receptive field.) b) same scenario as in part (a) but now compare the firing rate of a second order sensory neuron (take into account lateral inhibition).

Yes

2+2 is 4 -1 that’s 3 quick maths

there is no

explanation:

"menstrual cycle is a complex cycle that consists of several processes. order of occurrence of steps in menstrual cycle are as follows:

1. high progesterone levels maintain the endometrium lining of the uterus.

2. endometrium lining breaks down and low levels of estrogen stimulate the pituitary to release fsh and lh.

3. fsh and lh stimulates the follicles to develop and the oocyte to produce estrogen.

4. rising estrogen levels suppress fsh production and development of other follicles.

5. a spike in lh causes follicle to rupture.

6. a breakdown of corpus luteum causes progesterone level to drop."