In a population of skunks, there are striped and stripeless individuals. stripes are dominant to the absence of stripes. in this population, p = 0.8 and the frequency of heterozygotes is 0.25. this shows that the population is in hardy-weinberg equilibrium
a) true
b) false

False

Explanation:

Given,

Striped population is dominant over stripeless individuals.

Let the allele for striped population be represented by "S" and stripeless population be represented by "s"

p denotes the frequency of dominant allele

As per hardy Weinberg,  first equilibrium equation-

Now as per Hardy Weinberg, second equilibrium equation -

But this does not match with the frequency of heterozygotes given in the question i.e 0.25.

Hence, the statement is false

if your own plato the answer is b. the fern transitioned from sporophyte generation to gametophyte generation.