Using the equation cs2+3o2=co2+2so2 what is the percent yield of so2 if the burning of 12.5g of cs2 produces 15.12 g of so2

  = 71.96%

1 mole of CS2 = 76.133 g

1 mole of SO2 = 64.06 g

1 mole of CS2 reacts with 3 moles of Oxygen to produce 2 moles of SO2

Moles of CS2 in 12.5 g = 12.5/76.133

                                      =  0.164 moles

Mass of SO2 = 0.164 mol × 2 × 64.06

                      = 21.01168 g

Therefore;

Percentage yield of SO2

  = 15.12/21.01168 × 100%

  = 71.96%

the "power" of a lens is its resolution power, or its ability to distinguish between to closely located points. with the low power lens, it is likely you will see the rough form of the hay and maybe some movement of dots around the hay. however, when observed with the high power lens, the detailed features of the hay become visible and the microbes being grown are more clearly visible.

i hope this you