In pea plants, round is dominant to wrinkled and yellow is dominant to green. if two pea plants that are both heterozygous for both traits are crossed, what is the chance (out of 16) of an offspring that is homozygous round and homozygous green?
a. 1
b. 9
c. 3
d. 4

4 out of 16 of the offspring will be both homozygous round and homozygous green.

(below is my work)

S - Round

s - Wrinkled

C - Yellow

c - Green

both parents plants are SsCc

       S        s

C    SC      sC    x4

c     Sc       sc

16/4=4

4x1=4

Option D. 4

Explanation:

Let the alleles be: Round = R

                              Wrinlkled = r

                              Yellow    = Y

                              Green     = y

The crossing of the plants produces 1 in 4 chance of the orgnism possessing any one of the traits.

Thus, the option is 4

it has to be understood that the sea water contains a huge amount of sodium and chlorine ions and if they enter the cell of the atlantic cod fish, the cell will shrivel and the fish will die. to avoid such a condition, the fish uses active transport for the purpose of removing the ions against the gradient.

explanation:

the atlantic cod is not a maritime osmoconformer. its native application of salts is less than that of the seawater it lives in. it is continually falling water from the gills to the ocean via osmosis.

countering that, the fish is going to be swallowing seawater. but since its internal collection of salts is lower than seawater, the fish will want to go free of excess salt, and since that's going upon a gradient, then active transport, requiring energy, must be used to pump out the salt. much marine fish use the organs to filter out the salt and these fish discharge very straight urine.