Acouple plans to have a child. the mother is homozygous for an autosomal recessive mutation. the father is heterozygous for the same mutation. with respect to this mutation, what are the possible genotypes of any children they have? calculate the probability of each genotype's occurrence. show how you got your answer.

Answer:

Explanation:

Since the mother is homozygous her genotype would be hh and the father is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the possible genotypes of the children are Hh and hh as shown in the cross.

Note : An image is attached representing the cross in a Punnett square.

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2

Answer:

Explanation:

Since the mother is homozygous her genotype would be hh and the father is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the possible genotypes of the children are Hh and hh as shown in the cross.

Note : An image is attached representing the cross in a Punnett square.

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2

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