The snow goose (chen caerulescens) has both a blue and a white morph. inheritance is mendelian: bb and bb individuals are blue, while bb individuals are white. if 23 geese in a population of 142 are white, and 119 are blue, how many of the blue geese would you expect to be carriers of the b allele (i. e., bb heterozygotes)

We solve the problem using the Hardy-Wineberg equation.

Let us start with the homozygous recessive number of white trait,

∴ q² =   = 0.16

We have the frequency for white trait as q = 0.4

Solving for the frequency of blue trait by using the fact that,

p + q = 1

∴ p = 1 - q = 1 - 0.4 = 0.6

Now we can calculate 2pq in p² + 2pq + q², which is the frequency for heterozygous blue trait,

∴ 2pq = 2 x 0.6 x 0.4 = 0.48

And the homozygous blue trait is given by the expression,

∴ p² = 0.6² = 0.36

Hence, the carriers for the trait of blue are, 0.48 + 0.36 = 0.84, or 84% of 142.

∴ 84% of 142 =

Answer is 119.

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a) carbon, hydrogen

b) carbon, hydrogen, oxygen, nitrogen

c) carbon, hydrogen, oxygen, nitrogen, phosphorus

d) sugar

e) amino acid

f) nucleotide