The next generation of lizards has 1092 individuals with green scales and 108 individuals with blue scales. is the population in hardy-weinberg equilibrium? solve for p and q.

There are two equations necessary to solve a Hardy-Weinberg Equilibrium question:               p + q = 1

P is the frequency of the dominant allele.q is the frequency of the recessive allele.
P² is the frequency of individuals with the homozygous dominant genotype.
2pq is the frequency of individuals with the heterozygous genotype.
The q² is the frequency of individuals with the homozygous recessive genotype.

Given Data: 
Green individuals = 1092
Blue individuals    = 108

The frequency of individuals = individuals/total population

The frequency of Green individuals = 1092/1200

The frequency of Green individuals = 0.91

                                                        q² = 0.91
                                                     √ q² = √0.91
                                                          q = 0.953

Use the first Hardy-Weinberg equation:
                                                                 p + q        = 1
                                                                 p + 0.953 = 1
                                                                 p               = 1 - 0.953
                                                                 p               = 0.046

The answer would be interphase.