Advanced Placement (AP), 30.07.2019 00:30 loveeealyric744

Jim has been given the assignment to speak to his biology class on the function and structure of a cell. which of the following is the best approach he could take? a. jim copies several paragraphs from his biology book onto notecards and reads them quickly to the class to make sure he covers everything within the time limit. b. jim shares a very funny story about his brother, who failed a biology test because he studied from the wrong chapter the night before the test. c. jim starts out with a funny story, then uses pictures to describe in detail the function of a cell by comparing it to a factory in which each department has a specific function. d. jim starts out by explaining that a video he found will do a much better job explaining it than he would, and then plays a 20 minute video for the class.

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The answer is Jim starts out with a funny story, then uses pictures to describe in detail the function of a cell by comparing it to a factory in which each department has a specific function (C).

Answer from: samueldfhung

c. Jim starts out with a funny story, then uses pictures to describe in detail the function of a cell by comparing it to a factory in which each department has a specific function.

Explanation:

You may have noticed that you learn better the content taught in a school subject when the teacher teaches in a more relaxed way. That's because the relaxation makes you less tense and thus more relaxed to understand and record the whole subject.

Jim must keep this in mind when explaining the functions of the cell. For this reason we can say that he will succeed in explaining these functions if he finds a relaxed way to do so. So Jim's best bet is to start the explanation with a funny story and then use images to describe in detail the function of a cell, comparing it to a factory in which each department has a specific function.

Answer from: Quest

The answer is (d) 7/2======we have $f(x) = \begin{cases} x & \text{ for } x \le 0 \\ x + 1 & \text{ for } x \ \textgreater \ 0 \end{cases}$ we also have an integral $\displaystyle\int_{-2}^1 x\, f(x)\; dx$ notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum: $\displaystyle\int_{-2}^1 x\, f(x)\; dx = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx$ notice that for the piecewise function f, the function has the equationf(x) = x when x ≤ 0. so for the integral $\int_{-2}^0 x\, f(x)\; dx$ , f(x) = x so it changes into $\begin{aligned} \int_{-2}^0 x\, f(x)\; dx & = \int_{-2}^0 x \cdot x\; dx \\ & = \int_{-2}^0 x^2\; dx \\ & = \left[\frac{x^3}{3}\right]_{-2}^0 & & \text{\footnotesize antidifferentiate} \\ & = 0 - \frac{(-2)^3}{3} \\ & = \frac{8}{3} \end{aligned}$ for the piecewise function f, the function has the equationf(x) = x+1 when x > 0. for the integral $\int_{0}^1 x\, f(x)\; dx$ , we have $\begin{aligned} \int_{0}^1 x\, f(x)\; dx & = \int_{0}^1 x(x+1)\; dx \\ & = \int_{0}^1 (x^2+x)\; dx \\ & = \left[ \frac{x^3}{3} + \frac{x^2}{2}\right]_0^1 \\ & = \frac{1}{3} + \frac{1}{2} - 0 = \frac{5}{6} \end{aligned}$ therefore, back to our splitted integral: $\begin{aligned} \displaystyle\int_{-2}^1 x\, f(x)\; dx & = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx \\ & = \frac{8}{3} + \frac{5}{6} \\ & = \frac{7}{2} \end{aligned}$
Can anyone me on this ap calc question? ?

Can anyone me on this ap calc question? ?

Answer from: Quest

If it’s 15 minutes it would be 159

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