Aball is projected upward at time t = 0 s, from a point on a flat roof 10 m above the ground. the ball rises and then falls with insignificant air resistance, missing the roof, and strikes the ground. the initial velocity of the ball is 58.5 m/s consider all quantities as positive in the upward direction. at time t=5.97 s the vertical velocity of the ball is closest to

We can use a simple kinematic equation to find the velocity of the ball. v = v0 + at v = 58.5 m/s + (-9.80 m/s^2) (5.97 s) v = -0.006 m/s The negative sign means that the ball is heading down toward the ground. The small magnitude of the velocity means that the ball has reached the maximum height and is starting to fall back down toward the ground. The velocity of the ball is -0.006 m/s

The answer would be c.