A teacher chooses 4 different students to answer questions. There are 21 sophomores and 8 freshmen. Find the probability of the teacher choosing 2 sophomores, then 2 freshmen.

There are C(29, 4) = 29!/(4! (29 - 4)!) ways of selecting any 4 students from the total 21 + 8 = 29 students.

The teacher has C(21, 2) = 21!/(2! (21 - 2)!) ways of picking out 2 sophomores and C(8, 2) = 8!/(2! (8 - 2)!) ways of picking out 2 freshmen, so there are

C(21, 2) • C(8, 2) = 5880

possible ways of picking out 2 sophomore and 2 freshmen.

The probability of picking out a group of students like this is then

C(21, 2) • C(8, 2) / C(29, 4) = 280/1131 ≈ 0.2476

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