Advanced Placement (AP), 04.05.2021 23:20 akerner

Explain why reaction (1) has a negative /\S° value whereas reaction (II) has a positive /\S° value. I) 2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4H2O(1) II) 2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4 H2O(g) AS° = -387 J/molk AS0 = 89 J/molK

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Explain why reaction (1) has a negative /\S° value whereas reaction (II) has a positive /\S° value....

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More questions: Advanced Placement (AP) Another questions

Explain why reaction (1) has a negative /\S° value whereas reaction (II) has a positive /\S° value. I) 2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4H2O(1) II) 2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4 H2O(g) AS° = -387 J/molk AS0 = 89 J/molK​

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Another question on Advanced Placement (AP)

Explain why reaction (1) has a negative /\S° value whereas reaction (II) has a positive /\S° value. I) 2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4H2O(1) II) 2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4 H2O(g) AS° = -387 J/molk AS0 = 89 J/molK