If f(x)=x^2-x and g(x)=1/x and h(x) is defined with the expressions below, arrange the values of h'(1) from smallest to largest. 1) h(x)=f(x)-g(x) 2) h(x)=f(x)g(x) 3) h(x)=f(g(x))

F(x) = x²-x

g(x) =1/x

1) h(x) =f(x) -g(x) = (x²-x) - (1/x) = (x³-x²)/x (x≠0) =>
2)h(x) =f(x).g(x) =  (x²-x).(1/x) =x(x²-1)
3)h(x) = f(g(x)) = (1/x)²-(1/x)

Horizontal asymptote at  tells us that the original graph has been translated down.since  ,  are positive.  also we can say that the point  has a smaller  -coordinate than  .this means that the  transformed exponential function is increasing as it goes to the right. as it goes from  to , the value of the exponential function increases. it goes from to something bigger, . therefore, as  . the left hand would be the side that approaches the horizontal asymptote.so the answer is d

Iwould say either b or ci could be wrong let me know