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Ireayyy need , it's literally my last question and im stuck on it.
f(0)=3
f'(0)=5
f"(0)=7
h(x)=cos(kx)[f(x)]+sinx
find h'(x) at x=0.

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Answers: 3

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You know the right answer?
Ireayyy need , it's literally my last question and im stuck on it.
f(0)=3
f'(0)=5
...
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