Consider the following code segment. int[][] multi = new int[4][4];

for (int rows = 0; rows < 4; rows++)

{

for (int cols = 0; cols < 4; cols++)

{

if (cols == 0)

{

multi[rows][cols] = 0;

}

else if (cols == 1)

{

multi[rows][cols] = 1;

}

else if (cols == 2)

{

multi[rows][cols] = 2;

}

if ((rows % 2 == 0) && (cols % 2 == 0))

{

if ((rows >= 2) && (cols <= 2))

{

multi[rows][cols] = 9;

}

}

}

}

As a result of executing the code segment, how many elements in the two-dimensional (2D) array multi will store the value 9 ?

A) 0
B)1
C)2
D)4
E)6

If you are talking about typical sand you would find at the beach or in a river bed here on earth, there are some differences. i would say the first biggest difference is in composition and mineral make up. although the moon is largely made of the same materials as earth’s mantle and surface, the moon experiences very little weathering (no liquid water and virtually no atmosphere). “earth” sand is typically composed mostly of quartz grains. this is because quartz is highly resistant to both physical and chemical weathering. most of the other minerals originally with the quartz are broken down into fine clay and carried away, chemically eroded/ dissolved, or some combination of the two. this usually leaves only the quartz behind, and so most of the time when you see/think of sand, you are talking about quartz. without these weathering mechanisms on the moon, the “sand” (which is likely more silt or clay sized grains anyways) would consist of mostly other minerals like anorthosite, olivine, and proxene.

: )

Iwould say b but i’m not so sure

You're asking in the ap section, so i'll give the ap calculus-style answer. alternatively, you can find the vertex of the parabola and use the "y"-coordinate as the answer.

the maximum height can occur at a critical number, that is, a number  such that  .

the derivative of  can be calculated as follows:



find a value of  that is a zero of the derivative:


this is parabola that is opening downward; we can assume there is a maximum at  .

to find that maximum, calculate  .