Advanced Placement (AP), 22.11.2020 14:00 christyr2002

According to the Gottmans, what can couples do to help their marriages survive after the arrival of children?

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Marriage is indeed a type of agreement wherein two people decide to live together based on mutual interest. You have seen that the advent of a child in the household causes major dysfunction within relationships between couples.

When we investigate the cause of such a condition, we might discover several elements that have an impact on another's life.According to Dr. John Gottman, couples' relations might strengthen if they adopt certain preventive actions.Whenever a child is born to parents, it generates distance among couples because they begin to care for the child or each other, may blame, dispute, and feel alone. According to Dr. Gottman, spouses can subscribe to certain social and individual norms.

Criticism should be avoided.

Evaluation is a serious source of social separation because everyone needs care, attention, or support, but when couples start to criticize one another, a good environment can be created.

Appreciation:

Everybody requires applause since it allows us to feel loved and cared for in our work. As couples started to express gratitude, they helped to create a positive atmosphere.

Sexual behavior:

Sexual encounters between two people create intimacy or intense attachment, which aids in stress relief or intimate interaction. That the amount of sex is secondary to the quality of sexuality.

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Answer from: kcarstensen59070

Gottmans Method

Couples can help their marriages to survive after the arrival of children by engaging in the following habits:

1. Couples should remain physically affectionate, no matter the place.

2. Couples should continue to play and have fun together.

3. Cuddling always is good for couples.

4. Couples should prioritize sex. It is the glue for a healthy relationship between couples.

5. Good friends are better couples.

6. If you say "I love you" on a daily basis, mean it.

7. Couples should kiss passionately.

8. Couples should exchange romantic gifts and compliments.

Explanation:

If couples practice the above habits, among others, the arrival of children will be appreciated as fruits of their relationships and not obstacles. They will be able to love the children as they keep loving each other. The family is the center of bliss. With children, the family becomes more complete. Couples should embrace the responsibilities of raising children, without forgetting themselves and the reason they are together, to love.

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Answer from: Quest

Yep this is right you

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